下列叙述正确的是( )
【分析】A、根据高锰酸钾在加热条件下生成锰酸钾、二氧化锰和氧气,进行分析判断。
B、工业上分离液态空气制取氧气的原理,进行分析判断。
C、根据自然界中植物通过光合作用的原理,进行分析判断。
D、根据人体呼出的气体的成分,进行分析判断。
【解答】解:A、该化学方程式缺少反应条件,正确的化学方程式为
故选项说法错误。
B、工业上分离液态空气得到O2,利用的液态氮和液态氧沸点的不同,没有新物质生成,属于物理变化,故选项说法错误。
C、自然界中植物通过光合作用吸收CO2,释放O2,故选项说法正确。
D、人体呼出的气体中CO2的含量占4.5%左右,氧气含量为16%左右,人体呼出的气体中CO2的含量比O2低的多,故选项说法错误。
故选:C。
【点评】本题难度不大,了解氧气的工业制法、光合作用的原理、人体呼出的气体的成分等是正确解答本题的关键。
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